Pole Approximations: a quick look at the slope
Just finished reading a book on avalanches, Snow Sense,
and one point that was made a few times is, measure the slope!
So, I went out this past week and did so.
For those of you without your inclinometer (or those too lazy to dig it out)
I have come up with some approximations via some basic Trigonometry.
You can use your poles to measure the slope,
keeping 1 pole straight up, and the other horizontal (this makes them perpendicular).
Now then, where does the horizontal one meet the straight one???
(note: poles should not be plunged into the snow!)
This is the question that determines the slope.
Here are the answers:
If the horizontal one meets the straight one right on top, then it's 45 degrees.
Makes sense, right? It's a 1:1:root2 right triangle, or 45:45:90.
Here's how it breaks down, approximately:
1/1 ==> 45 degrees
3/4 ==> 37 degrees
2/3 ==> 33.5 degrees
1/2 ==> 26.5 degrees
less than that, get on the lift already!
And this deserves to be here.

Originally Posted by
upallnight
Good info for rough approximations.
Note: For those who find themselves on some steeper terrain, you can also use this method for slopes > 45 degrees.
If the vertical pole intersects the horizontal pole at approximately...
...the 3/4-point of the horizontal pole ==> 53 degrees
...the 2/3-point of the horizontal pole ==> 56.5 degrees
...the mid-point of the horizontal pole ==> 63.5 degrees (yikes!)
It's pretty easy to get the vertical pole plumb (just dangle the pole by its strap); getting the horizontal pole level is tougher.
Just thought I'd share that, because it was bugging me.
It might be a good idea to mark your poles at those designations,
because the eye can lie. Nothing some duct tape can't handle.
As for keeping the poles straight up/vertical, and horizontal/flat, bring a level (torpedo).
Last edited by TeleAl; 04-19-2006 at 10:03 AM.
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