Originally Posted by
smitchell333
A) each person will count the # of others with blue eyes (ie for those with blue eyes = N). And the # of others with Green, and Brown eyes).
B) once you know these you will logically know that theoretically you have 4 options - you have:
1) Blue eyes, 2) Green eyes, 3) Brown eyes, 4) you have some other eye color and are the only one. There is no way of ever knowing for CERTAIN whether you have any eye color, other than guessing and presenting yourself as knowing you have an eye color and if you get off - you know.
C) Therefore you (assuming you want off the island) logically construct a plan to escape in the shortest possible time:
1) Night one - present yourself as either randomly blue or brown - you have 0 information to suggest either way but you know that statistically brown and blue are best represented and therefore your best guess - so by laws of chance approximately 50 blue and 50 brown will get off.
2) Night two - present yourself as the other option of the blue/brown from what you presented the day before -you have 0 information to suggest either way but you know that statistically brown and blue are best represented and therefore your best guess - so the remaining 50 blue and 50 brown will get off.
3) Night three - Doctor is the only one remaining - he will present himself as randomly chosen color other than blue, brown, green - "I have grey eyes" - the doctor could get off, but only by a lucky guess.
5) Day 4, etc - Dr presents himself as randomly chosen color other than blue, brown, green - "I have grey eyes" - the doctor could get off, but only by a lucky guess - he could be here forever but probably will be off by day 8 or 9 as there are really only a handful of common eye colors to guess.